Tomáš Holý wrote: > jestli pouzivas PHP tak by to slo resit takhle > <?php > $ip = $_SERVER['REMOTE_ADDR']; > if($ip == '192.168.0.1' || $ip = '192.168.0.2' || $ip = '192.168.0.3') { --------------------------------------- dokazete si takto predstavit 10 a vice IP-in? fuj, ja jo a je mi spatne ;))) cistejsi to, podle mne, bude takto: <?php $bad_ip = array ( '212.47.28.2', '212.47.28.10', ); if (TRUE == in_array($_SERVER['REMOTE_ADDR'], $bad_ip)) { echo 'tahni'; } else { echo 'a tak pojd ;)'; } ?> -- -h!- http://www.hyneklipa.cz/ ICQ: 289612872Received on Thu, 30 Sep 2004 15:59:33 +0200
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