Michal Bilcik <krutohlav@host.sk>: > A co ked bude tabulka "druha" takato: > > id druh > --------- > 1 jablko > 2 hruska > 3 rybiz > 4 rybiz > 5 rybiz > > ?? To me nenapadlo, ale ona nikdy nebude. Teda nemela by byt ;o) Jedna se o jedinecny hash, takze tahle situace by nastat nemela. > Ak raz: > > SELECT b.druh FROM druha AS b LEFT JOIN prvni AS a ON a.druh = b.druh > WHERE a.druh IS NULL GROUP BY a.druh Funguje. > Ak vsetky vyskyty: > > SELECT b.druh FROM druha AS b LEFT JOIN prvni AS a ON a.druh = b.druh > WHERE a.druh IS NULL Funguje. Presne to jsem potreboval, diky. -pp21-Received on Sun, 7 Mar 2004 18:19:12 +0100
This archive was generated by hypermail 2.1.8 : 07. 03. 2004, 18:19 CET