toto je kusok kodu, problem mam asi s predavanim premennych, lebo select count(*) from user where active=1 mi v mysql funguje... Vie niekto pomoct? Diky $result = ''; $connection = mysql_pconnect(SQL_SERVER, SQL_UID, SQL_PWD); mysql_select_db(SQL_DB, $connection); $sql = 'select count(*) total from user where active=1'; $query = mysql_query($sql); $record = mysql_fetch_array($query); $result = 'There are a total of ' . $record['total'] . ' pictures and '; $sql = "select sum(votecount) total from user"; $query = mysql_query($sql); $record = mysql_fetch_array($query); $result .= $record['total'] . " votes in the system"; return $result;
This archive was generated by hypermail 2.1.2 : 04. 09. 2001, 05:36 CEST